Codility - 코딩테스트 기록용 4일차

 FrogJmp

Count minimal number of jumps from position X to Y.

int값 세개 , X, Y, D값을 입력받아

X의 위치에서 Y까지 D만큼씩 이동했을떄 몇번 이동해야하는지 구하는 문제

 - 내가 푼 코드

public static int solution(int X, int Y, int D) {

int result = ((Y - X) / D) ;

int cha = ((Y - X) % D);

if(cha > 0) {

result++;

}

if(X >= Y) {

result = 0;

}

return result;

}

- 다른사람이 푼 코드 

public int solution(int X, int Y, int D) {

        if(X == Y) return 0;

     return (Y-X)%D == 0? (Y-X)/D : (Y-X)/D + 1;

}

결국 똑같은거지? 

- Swift 버전

func solution(X:Int, Y:Int, D:Int) -> Int{

    var result = (Y-X)/D

    let cha = (Y-X)%D

    if cha > 0{

        result += 1

    }

    

    if X >= Y{

        result = 0

    }

    return result;

}

Codility - 코딩테스트 기록용 3일차

 OddOccurrencesInArray

-Find value that occurs in odd number of elements.

N개의 배열에서 짝을 이루지 않는 값을 찾아내기

프로그래머스에서 몇개 풀고왔는데 비슷한 문제가 나왔다

Map을 사용해서 getOrDefault함수를 사용했다

그리고 마지막엔 나머지값이 1인 값을 찾아내기!

public int solution(int[] A) { // write your code in Java SE 8 Map<Integer, Integer> map = new HashMap<>(); for(int i=0; i<A.length; i++){ map.put(A[i], map.getOrDefault(A[i], 0) + 1); } for(int key : map.keySet()){ if(map.get(key) % 2 == 1) {

                return key;

            }

} return -1; }

다른사람이 짠 코드도 비슷하다

하하 이번엔 비슷했다.

SWIFT버전

public func solution(_ A : inout [Int]) -> Int {
    // write your code in Swift 4.2.1 (Linux)
    var map = Dictionary<Int, Int>();

    A.forEach { index in
    map[index] = (map[index, default: 0]) + 1
    }
    
    var result = -1
    map.forEach { (key: Int, value: Int) in
        if(value % 2 == 1){
            result = key
        }
    
    }
    return result
}

Codility - 코딩테스트 기록용 2일차

CyclicRotation

 Rotate an array to the right by a given number of steps.

-배열을 주어진 숫자만큼 돌려서 원하는 값을 찾는다

-변경되어야 할 배열순사를 지켜야했음 

-내가 짠 코드

public static int[] solution(int[] A, int K) {

        // write your code in Java SE 8

        int[] result = new int[A.length];

        System.err.println("lenth = "+A.length);

        if(A.length == K){

            return A;

        }     

        

        for (int i = 0; i < A.length ; i++) {

        result[(i+K) % A.length] = A[i];

        System.err.println("i = "+i+" = "+result[i]);

        }

        for (int i = 0; i < result.length; i++) {

System.err.println("a["+i+"] = " +result[i]);

}

        return result;

    }

--다른사람이 짠 코드

class Solution {
    public int[] solution(int[] A, int K) {
        // write your code in Java SE 8
        int len = A.length;
        if(len == 0 || K % len == 0) return A;
        int [] ans = new int [len];

        K = K % len;

        for (int i=0; i< len; i++){
            ans[(i+K) % len] = A[i];
        }
        return ans;
    }
}

역시 개깔끔...나는 멀었나보다

-swift 코드 

public func solution(_ A : inout [Int], _ K : Int) -> [Int] {
    // write your code in Swift 4.2.1 (Linux)
    
    if A.count == K{
        return A
    }
    var result = A
    for i in 0..<A.count{
        let num = (i+K)%A.count
        result[num] = A[i]
    }
    return result
}

Codility - 코딩테스트 기록용 1일차

 BinaryGap

Find longest sequence of zeros in binary representation of an integer.

이진법으로 변환 후 1과 1사이의 0의 값을 추출한다.

내가 푼 방법 

public static int solution(int N) {

        // write your code in Java SE 8

String binary = Integer.toBinaryString(N);

List<Integer> aArray = new ArrayList();

int result = 0;

for (int i = 0; i < binary.length(); i++) {

if(binary.charAt(i) == '1') {

aArray.add(i);

}

}

int max = 0;

int val = 0;

for (int i = 0; i < aArray.size() -1; i++) {

if(i == 0) {

max = binary.substring(aArray.get(i), aArray.get(i+1)).length() -1;

}else {

val = binary.substring(aArray.get(i), aArray.get(i+1)).length() -1;

}

if(i > 0) {

max = Integer.max(max, val);

}

}

if(aArray.size() < 2) {

max = 0;

}

return max;

    }

-> 다른 사람이 푼 코드 

class Solution {
    public int solution(int N) {
        // write your code in Java SE 8

        String binaryNum = Integer.toBinaryString(N);
        int temp = 0;
        int maxLen = temp;

        for(int i=1; i< binaryNum.length(); i++){
            if(binaryNum.charAt(i) == '0') temp++;
            else{
                maxLen = Math.max(maxLen, temp);
                temp = 0; 
            }
        }
        return maxLen;
    }
}

개깔끔.. 왜 저생각을 못했지.. 분발하자!

SWIFT 버전

public func solution(_ N: Int) ->Int{

    var result = 0

    let binary = String(N, radix: 2, uppercase: true)

    var tmp = 0;

    for char in binary {

        if char == "0"{

            tmp += 1

        }else{

            result = max(result, tmp)

            tmp = 0

        }

    }

    return result

}

Privacy Policy

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맥북에서 Android Jni사용

처음으로 Android Jni를 사용하는데
헤더 파일이 생성이 안된다.....

왜지??

프로젝트 bin/classes 에서

javah -classpath ${android_home}/android.jar com.ex.hellojni

Could not find class................

윈도우에서 해보니 정상동작...뭐지??

맥에서는 경로를 못찾나보다;;

구글링 구글링...

세미콜론과 점을 찍으란다

javah -classpath ${android_home}/android.jar;. com.ex.hellojni

역시 실패

다시 구글링...

콜론과 점을 찍으란다

javah -classpath ${android_home}/android.jar:. com.ex.hellojni

오...성공!! ㅋㅋㅋ

참고로 ndk-bulider를 실행하기 위해선 .bash_profile에 NDK_HOME이 등록되어있어야한다.

오늘도 배웠다!!

참조 사이트

http://stackoverflow.com/questions/7635624/android-javah-doesnt-find-my-class

OC4J war file배포하기

1. oc4j instance 생성

$oracle_home/bin/createinstance -instanceName oc4japp01

2. war file 복사

아래 경로로 war file 복사

$oracle_home/j2ee/oc4japp01/application/

3. Application.xml 파일수정

$oracle_home/j2ee/oc4japp01/config/application.xml

...

<web-module id ="testWeb" path="../../oc4japp01/applications/test.war"/>

...

4. default-web-site.xml 파일수정

$oracle_home/j2ee/oc4japp01/config/default-web-site.xml

...

<default-web-app application="default" name="defaultWebApp" root="/j2ee"/>

<web-app application="default" name="testWeb" load-on-startup="true" root="/test"/>

...

5. opmn stop & opmn start

명령어

$oracle_home/opmn/bin opmnctl stopall

$oracle_home/opmn/bin opmnctl startall

--------------------------------------------------------------

포트 번호는 $oracle_home/Apache/Apache/conf/httpd.conf 안에 listen 과 port를 참고

windows 기준으로 작성됨